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Factoring a Pair of Planes into Linear Equations

  1. Once a General Quadratic Equation in 3 Variables has been identified as representing a Pair of Planes, it can be Factored into it's 2 Constituent Real or Complex Linear Equations.
  2. Let consider a General Quadratic Equation in 3 Variables representing a Pair of Planes given as follows

    Ax2+By2+Cz2+Dxy+Exz+Fyz+Gx+Hy+Iz+K=0   ...(1)

    which has to be Factored into it's corresponding 2 Linear Equations given as follows

    A1x+B1y+C1z+D1=0   ...(2)

    A2x+B2y+C2z+D2=0   ...(3)

    Now, the Coefficients and the Constant of the equation (1) above can be given in terms of Coefficients and the Constants of the Linear Equations (2) and (3) above as follows

    A=A1A2   ...(4)

    B=B1B2   ...(5)

    C=C1C2   ...(6)

    D=A1B2+A2B1   ...(7)

    E=A1C2+A2C1   ...(8)

    F=B1C2+B2C1   ...(9)

    G=A1D2+A2D1   ...(10)

    H=B1D2+B2D1   ...(11)

    I=C1D2+C2D1   ...(12)

    K=D1D2   ...(13)

    The following gives the steps of Finding the Values of the Coefficients and Constants A1,A2,B1,B2,C1,C2,D1 and D2 of the Linear Equations (2) and (3) above
    1. Normalize the General Quadratic Equation in 3 Variables given in equation (1).
    2. If the Coefficient of x2 (A) in the equation (1) is Not Zero, then the Coefficient of x2 (A) in the Normalized version of equation (1) becomes 1. Since A=A1A2, the Values of the Coefficients A1 and A2 can be set as 1 as well. Accordingly, the Coefficients and the Constant of the Normalized version of equation (1) above can be given in terms of Coefficients and the Constants of the Linear Equations as follows

      A=1   ...(14)

      B=B1B2   ...(15)

      C=C1C2   ...(16)

      D=B1+B2   ...(17)

      E=C1+C2   ...(18)

      F=B1C2+B2C1   ...(19)

      G=D1+D2   ...(20)

      H=B1D2+B2D1   ...(21)

      I=C1D2+C2D1   ...(22)

      K=D1D2   ...(23)

      Now, a Quadratic Equation can be formed by using the Values of Coefficient G and Constant K in equations (20) and (23) (which give the Sum of the Roots and Product of the Roots of the Quadratic Equation respectively) as follows

      x2Gx+K=0   ...(24)

      x2(D1+D2)x+D1D2=0   ...(25)

      The Values of Constants D1 and D2 can be found out Finding the Roots of Quadratic Equation (24) above.

      Now, if Values of either D1 or D2 or Both are Not Zero then the Values of Coefficients B1 and B2 can be found out by Solving the System of Linear Equations given by equations (7) and (11) above as follows

      A1B2+A2B1=D   ...(from equation 7)

      B1D2+B2D1=H   ...(from equation 11)

      The above equations can be given in form of a Matrix Equation as follows

      [A2A1D2D1][B1B2]=[DH]   ...(26)

      [B1B2]=[A2A1D2D1]1[DH]   ...(27)

      Also, the Values of Coefficients C1 and C2 can be found out by Solving the System of Linear Equations given by equations (8) and (12) above as follows

      A1C2+A2C1=E   ...(from equation 8)

      C1D2+C2D1=I   ...(from equation 12)

      The above equations can be given in form of a Matrix Equation as follows

      [A2A1D2D1][C1C2]=[EI]   ...(28)

      [C1C2]=[A2A1D2D1]1[EI]   ...(29)

      Otherwise, if Values of Both D1 and D2 are Zero, a Quadratic Equation can be formed by using the Values of Coefficients D and B in equations (17) and (15) (which give the Sum of the Roots and Product of the Roots of the Quadratic Equation respectively) as follows

      x2Dx+B=0   ...(30)

      x2(B1+B2)x+B1B2=0   ...(31)

      The Values of Coefficients B1 and B2 can be found out Finding the Roots of Quadratic Equation (30) above.

      Similarly, a Quadratic Equation can be formed by using the Values of Coefficients E and C in equations (18) and (16) (which give the Sum of the Roots and Product of the Roots of the Quadratic Equation respectively) as follows

      x2Ex+C=0   ...(32)

      x2(C1+C2)x+C1C2=0   ...(33)

      The Values of Coefficients C1 and C2 can be found out Finding the Roots of Quadratic Equation (32) above.

      The values of B1,C1 and B2,C2 can be matched and verified by evaluating equation (19) above.
    3. If the Coefficient of x2 (A) in the equation (1) is Zero and Coefficient of y2 (B) in the equation (1) is Not Zero, then the Coefficient of y2 (B) in the Normalized version of equation (1) becomes 1. Since B=B1B2 , the Values of the Coefficients B1 and B2 can be set as 1 as well. Accordingly, the Coefficients and the Constant of the Normalized version of equation (1) above can be given in terms of Coefficients and the Constants of the Linear Equations as follows

      A=A1A2   ...(34)

      B=1   ...(35)

      C=C1C2   ...(36)

      D=A1+A2   ...(37)

      E=A1C2+A2C1   ...(38)

      F=C1+C2   ...(39)

      G=A1D2+A2D1   ...(40)

      H=D1+D2   ...(41)

      I=C1D2+C2D1   ...(42)

      K=D1D2   ...(43)

      Now, a Quadratic Equation can be formed by using the Values of Coefficient H and Constant K in equations (41) and (43) (which give the Sum of the Roots and Product of the Roots of the Quadratic Equation respectively) as follows

      x2Hx+K=0   ...(44)

      x2(D1+D2)x+D1D2=0   ...(45)

      The Values of Constants D1 and D2 can be found out Finding the Roots of Quadratic Equation (44) above.

      Now, if Values of either D1 or D2 or Both are Not Zero then the Values of Coefficients A1 and A2 can be found out by Solving the System of Linear Equations given by equations (7) and (10) above as follows

      A1B2+A2B1=D   ...(from equation 7)

      A1D2+A2D1=G   ...(from equation 10)

      The above equations can be given in form of a Matrix Equation as follows

      [B2B1D2D1][A1A2]=[DG]   ...(46)

      [A1A2]=[B2B1D2D1]1[DG]   ...(47)

      Also, the Values of Coefficients C1 and C2 can be found out by Solving the System of Linear Equations given by equations (9) and (12) above as follows

      B1C2+B2C1=F   ...(from equation 9)

      C1D2+C2D1=I   ...(from equation 12)

      The above equations can be given in form of a Matrix Equation as follows

      [B2B1D2D1][C1C2]=[FI]   ...(48)

      [C1C2]=[B2B1D2D1]1[FI]   ...(49)

      Otherwise, if Values of Both D1 and D2 are Zero, a Quadratic Equation can be formed by using the Values of Coefficients D and A in equations (37) and (34) (which give the Sum of the Roots and Product of the Roots of the Quadratic Equation respectively) as follows

      x2Dx+A=0   ...(50)

      x2(A1+A2)x+A1A2=0   ...(51)

      The Values of Coefficients A1 and A2 can be found out Finding the Roots of Quadratic Equation (50) above.

      Similarly, a Quadratic Equation can be formed by using the Values of Coefficients F and C in equations (39) and (36) (which give the Sum of the Roots and Product of the Roots of the Quadratic Equation respectively) as follows

      x2Fx+C=0   ...(52)

      x2(C1+C2)x+C1C2=0   ...(53)

      The Values of Coefficients C1 and C2 can be found out Finding the Roots of Quadratic Equation (52) above.

      The values of A1,C1 and A2,C2 can be matched and verified by evaluating equation (38) above.
    4. If the Coefficients of Both x2 (A) and y2 (B) in the equation (1) are Zero and Coefficient of z2 (C) in the equation (1) is Not Zero, then the Coefficient of z2 (C) in the Normalized version of equation (1) becomes 1. Since C=C1C2 , the Values of the Coefficients C1 and C2 can be set as 1 as well. Accordingly, the Coefficients and the Constant of the Normalized version of equation (1) above can be given in terms of Coefficients and the Constants of the Linear Equations as follows

      A=A1A2   ...(54)

      B=B1B2   ...(55)

      C=1   ...(56)

      D=A1B2+A2B1   ...(57)

      E=A1+A2   ...(58)

      F=B1+B2   ...(59)

      G=A1D2+A2D1   ...(60)

      H=B1D2+B2D1   ...(61)

      I=D1+D2   ...(62)

      K=D1D2   ...(63)

      Now, a Quadratic Equation can be formed by using the Values of Coefficient I and Constant K in equations (41) and (43) (which give the Sum of the Roots and Product of the Roots of the Quadratic Equation respectively) as follows

      x2Ix+K=0   ...(64)

      x2(D1+D2)x+D1D2=0   ...(65)

      The Values of Constants D1 and D2 can be found out Finding the Roots of Quadratic Equation (64) above.

      Now, if Values of either D1 or D2 or Both are Not Zero then the Values of Coefficients A1 and A2 can be found out by Solving the System of Linear Equations given by equations (8) and (10) above as follows

      A1C2+A2C1=E   ...(from equation 8)

      A1D2+A2D1=G   ...(from equation 10)

      The above equations can be given in form of a Matrix Equation as follows

      [C2C1D2D1][A1A2]=[EG]   ...(66)

      [A1A2]=[C2C1D2D1]1[EG]   ...(67)

      Also, the Values of Coefficients B1 and B2 can be found out by Solving the System of Linear Equations given by equations (9) and (11) above as follows

      B1C2+B2C1=F   ...(from equation 9)

      B1D2+B2D1=H   ...(from equation 11)

      The above equations can be given in form of a Matrix Equation as follows

      [C2C1D2D1][B1B2]=[FH]   ...(68)

      [B1B2]=[C2C1D2D1]1[FH]   ...(69)

      Otherwise, if Values of Both D1 and D2 are Zero, a Quadratic Equation can be formed by using the Values of Coefficients E and A in equations (58) and (54) (which give the Sum of the Roots and Product of the Roots of the Quadratic Equation respectively) as follows

      x2Ex+A=0   ...(70)

      x2(A1+A2)x+A1A2=0   ...(71)

      The Values of Coefficients A1 and A2 can be found out Finding the Roots of Quadratic Equation (70) above.

      Similarly, a Quadratic Equation can be formed by using the Values of Coefficients F and B in equations (59) and (55) (which give the Sum of the Roots and Product of the Roots of the Quadratic Equation respectively) as follows

      x2Fx+B=0   ...(72)

      x2(B1+B2)x+B1B2=0   ...(73)

      The Values of Coefficients B1 and B2 can be found out Finding the Roots of Quadratic Equation (72) above.

      The values of A1,B1 and A2,B2 can be matched and verified by evaluating equation (57) above.
    5. If the Coefficients of Both x2 (A), y2 (B) and z2 (C) in the equation (1) are Zero and Coefficient of xy (D) in the equation (1) is Not Zero, then the Coefficient of xy (D) in the Normalized version of equation (1) becomes 1. Under such condition, one of the following 2 things can be done

      Either we can set A1=B2=1 and A2=B1=0. Accordingly, the Coefficients and the Constant of the Normalized version of equation (1) above can be given in terms of Coefficients and the Constants of the Linear Equations as follows

      A=0   ...(74)

      B=0   ...(75)

      C=0   ...(76)

      D=1   ...(77)

      E=C2   ...(78)

      F=C1   ...(79)

      G=D2   ...(80)

      H=D1   ...(81)

      I=C1D2+C2D1   ...(82)

      K=D1D2   ...(83)

      Under such condition, the Value of C1=F, C2=E, D1=H and D2=G as given by equations (79), (78), (81) and (80) above respectively.

      Otherwize, we can set A1=B2=0 and A2=B1=1. Accordingly, the Coefficients and the Constant of the Normalized version of equation (1) above can be given in terms of Coefficients and the Constants of the Linear Equations as follows

      A=0   ...(74)

      B=0   ...(75)

      C=0   ...(76)

      D=1   ...(77)

      E=C1   ...(78)

      F=C2   ...(79)

      G=D1   ...(80)

      H=D2   ...(81)

      I= C_1D_2+C_2_D_1   ...(82)

      K=D1D2   ...(83)

      Under such condition, the Value of C1=E, C2=F, D1=G and D2=H as given by equations (78), (79), (80) and (81) above respectively.
    6. If the Coefficients of Both x2 (A), y2 (B), z2 (C) and xy (D) in the equation (1) are Zero and Coefficient of xz (E) in the equation (1) is Not Zero, then the Coefficient of xz (E) in the Normalized version of equation (1) becomes 1. Under such condition, one of the following 2 things can be done

      Either we can set A1=C2=1 and A2=C1=0. Accordingly, the Coefficients and the Constant of the Normalized version of equation (1) above can be given in terms of Coefficients and the Constants of the Linear Equations as follows

      A=0   ...(84)

      B=0   ...(85)

      C=0   ...(86)

      D=B2   ...(87)

      E=1   ...(88)

      F=B1   ...(89)

      G=D2   ...(90)

      H=B1D2+B2D1   ...(91)

      I=D1   ...(92)

      K=D1D2   ...(93)

      Under such condition, the Value of B1=F, B2=D, D1=I and D2=G as given by equations (89), (87), (92) and (90) above respectively.

      Otherwize, we can set A1=C2=0 and A2=C1=1. Accordingly, the Coefficients and the Constant of the Normalized version of equation (1) above can be given in terms of Coefficients and the Constants of the Linear Equations as follows

      A=0   ...(94)

      B=0   ...(95)

      C=0   ...(96)

      D=B1   ...(97)

      E=1   ...(98)

      F=B2   ...(99)

      G=D1   ...(100)

      H=B1D2+B2D1   ...(101)

      I=D2   ...(102)

      K=D1D2   ...(103)

      Under such condition, the Value of B1=D, B2=F, D1=G and D2=I as given by equations (97), (99), (100) and (102) above respectively.

    7. If the Coefficients of Both x2 (A), y2 (B), z2 (C), xy (D) and xz (E) in the equation (1) are Zero and Coefficient of yz (F) in the equation (1) is Not Zero, then the Coefficient of yz (F) in the Normalized version of equation (1) becomes 1. Under such condition, one of the following 2 things can be done

      Either we can set B1=C2=1 and B2=C1=0. Accordingly, the Coefficients and the Constant of the Normalized version of equation (1) above can be given in terms of Coefficients and the Constants of the Linear Equations as follows

      A=0   ...(104)

      B=0   ...(105)

      C=0   ...(106)

      D=A2   ...(107)

      E=A1   ...(108)

      F=1   ...(109)

      G=A1D2+A2D1   ...(110)

      H=D2   ...(111)

      I=D1   ...(112)

      K=D1D2   ...(113)

      Under such condition, the Value of A1=E, A2=D, D1=I and D2=H as given by equations (108), (107), (112) and (111) above respectively.

      Otherwize, we can set B1=C2=0 and B2=C1=1. Accordingly, the Coefficients and the Constant of the Normalized version of equation (1) above can be given in terms of Coefficients and the Constants of the Linear Equations as follows

      A=0   ...(114)

      B=0   ...(115)

      C=0   ...(116)

      D=A1   ...(117)

      E=A2   ...(118)

      F=1   ...(119)

      G=A1D2+A2D1   ...(120)

      H=D1   ...(121)

      I=D2   ...(122)

      K=D1D2   ...(123)

      Under such condition, the Value of A1=D, A2=E, D1=H and D2=I as given by equations (117), (118), (121) and (122) above respectively.

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