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Circular Permutations Without Repeatition

  1. Circular Permutations Without Repeatition refer to All Distinct Cyclic Arrangements of a given Set of Distinct Items such that Any One Item can occur Only Once in a given Cyclic Arrangement. Given \(N\) Number of Distinct Items , the Count of Circular Permutations Without Repeatition for \(R\) Items taken from \(N\) Items (where \(R \leq N\)) is calculated as follows

    Number of Linear Permutations/Arrangements Possible for \(N\) Distinct Items taken \(R\) Items at a time= \(P(N,R)\) =\(\frac{N!}{(N-R)!}\)

    Length of any Linear Permutation/Arrangement of \(R\) Distinct Items = \(R\)

    \(\therefore\) Number of Cyclic Arrangements Possible for any one Linear Permutation/Arrangement of \(R\) Distinct Items = \(R\)

    \(\therefore\) Number of Linear Permutations that Get Merged into Single Cyclic Permutation/Arrangement as they Represent the Same Cycle = \(R\)

    Hence, Total Number of Distinct Cyclic Arrangements Possible for \(N\) Distinct Items taken \(R\) Items at a time =

    \(\frac{Total\hspace{.1cm}Number\hspace{.1cm}of\hspace{.1cm}Linear\hspace{.1cm}Permutations\hspace{.1cm}Possible\hspace{.1cm}for\hspace{.1cm}N\hspace{.1cm}Distinct\hspace{.1cm}Items\hspace{.1cm}taken\hspace{.1cm}R\hspace{.1cm}Items\hspace{.1cm}at\hspace{.1cm}a\hspace{.1cm}time} {Total\hspace{.1cm}Number\hspace{.1cm}of\hspace{.1cm}Linear \hspace{.1cm}Permutations\hspace{.1cm}Getting\hspace{.1cm}Merged\hspace{.1cm}into\hspace{.1cm}Single\hspace{.1cm}Cyclic\hspace{.1cm}Permutation}= \frac{P(N,R)}{R}=\frac{N!}{R(N-R)!}\)

    When \(R=N\), Total Number of Distinct Cyclic Arrangements Possible for \(N\) Distinct Items =

    \(\frac{Total\hspace{.1cm}Number\hspace{.1cm}of\hspace{.1cm}Linear\hspace{.1cm}Permutations\hspace{.1cm}Possible\hspace{.1cm}for\hspace{.1cm}N\hspace{.1cm}Distinct\hspace{.1cm}Items} {Total\hspace{.1cm}Number\hspace{.1cm}of\hspace{.1cm}Linear \hspace{.1cm}Permutations\hspace{.1cm}Getting\hspace{.1cm}Merged\hspace{.1cm}into\hspace{.1cm}Single\hspace{.1cm}Cyclic\hspace{.1cm}Permutation}=\frac{N!}{N(N-N)!}=\frac{N!}{N}=(N-1)!\)

  2. Circular Permutations are called Orientation Independent if Every Clockwise Cricular Arrangement and their Corresponding Counter-Clockwise Circular Arrangement are considered to be a Single Permutation. Since Every 2 Permutations are considered to be a Single Permutation , therefore

    Total Orientation Independent Circular Permutations Without Repeatition \(=\frac{P(N,R)}{2R}=\frac{N!}{2R(N-R)!}\)   (when \(R\leq N\))
    OR
    Total Orientation Independent Circular Permutations Without Repeatition \(=\frac{N!}{2N(N-N)!}=\frac{(N-1)!}{2}\)   (when \(R=N\))
Related Topics and Calculators
Fundamental Principle of Counting, Concept of Factorial, Permutation and Combination,    Linear Permutations Without Repeatition,    Linear Permutations With Unrestricted Repeatition,    Linear Permutations With Restricted Repeatition,    Circular Permutations With Unrestricted Repeatition,    Combinations Without Repeatition,    Combinations With Unrestricted Repeatition,    Using Generating Functions to Find Combinations, Count of Combinations and Count of Linear Permutations,    Permutation Tables, Permutation Cycles and Transpositions,    Decomposition of Permutation/Permutation Cycles into Transpositions,    Product of Permutations, Permutation Cycles and Transpositions,    Inverse and Order of a Permutation,    Permutations and Permutation Matrices
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