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Necklace Symmetry Permutations

  1. Necklace Symmetry Permutations refer to All Distinct Cyclic Arrangements of a given Set of Distinct Items such that Any One Item can occur Only Once in a given Cyclic Arrangement. Given \(N\) Number of Distinct Items , the Count of Circular Permutations Without Repeatition for \(R\) Items taken from \(N\) Items (where \(R \leq N\)) is calculated as follows

    Number of Linear Permutations/Arrangements Possible for \(N\) Distinct Items taken \(R\) Items at a time= \(P(N,R)\) =\(\frac{N!}{(N-R)!}\)

    Length of any Linear Permutation/Arrangement of \(R\) Distinct Items = \(R\)

    \(\therefore\) Number of Cyclic Arrangements Possible for any one Linear Permutation/Arrangement of \(R\) Distinct Items = \(R\)

    \(\therefore\) Number of Linear Permutations that Get Merged into Single Cyclic Permutation/Arrangement as they Represent the Same Cycle = \(R\)

    Hence, Total Number of Distinct Cyclic Arrangements Possible for \(N\) Distinct Items taken \(R\) Items at a time =

    \(\frac{Total\hspace{.1cm}Number\hspace{.1cm}of\hspace{.1cm}Linear\hspace{.1cm}Permutations\hspace{.1cm}Possible\hspace{.1cm}for\hspace{.1cm}N\hspace{.1cm}Distinct\hspace{.1cm}Items\hspace{.1cm}taken\hspace{.1cm}R\hspace{.1cm}Items\hspace{.1cm}at\hspace{.1cm}a\hspace{.1cm}time} {Total\hspace{.1cm}Number\hspace{.1cm}of\hspace{.1cm}Linear \hspace{.1cm}Permutations\hspace{.1cm}Getting\hspace{.1cm}Merged\hspace{.1cm}into\hspace{.1cm}Single\hspace{.1cm}Cyclic\hspace{.1cm}Permutation}= \frac{P(N,R)}{R}=\frac{N!}{R(N-R)!}\)

    When \(R=N\), Total Number of Distinct Cyclic Arrangements Possible for \(N\) Distinct Items =

    \(\frac{Total\hspace{.1cm}Number\hspace{.1cm}of\hspace{.1cm}Linear\hspace{.1cm}Permutations\hspace{.1cm}Possible\hspace{.1cm}for\hspace{.1cm}N\hspace{.1cm}Distinct\hspace{.1cm}Items} {Total\hspace{.1cm}Number\hspace{.1cm}of\hspace{.1cm}Linear \hspace{.1cm}Permutations\hspace{.1cm}Getting\hspace{.1cm}Merged\hspace{.1cm}into\hspace{.1cm}Single\hspace{.1cm}Cyclic\hspace{.1cm}Permutation}=\frac{N!}{N(N-N)!}=\frac{N!}{N}=(N-1)!\)

  2. Circular Permutations are called Orientation Independent if Every Clockwise Cricular Arrangement and their Corresponding Counter-Clockwise Circular Arrangement are considered to be a Single Permutation. Since Every 2 Permutations are considered to be a Single Permutation , therefore

    Total Orientation Independent Circular Permutations Without Repeatition \(=\frac{P(N,R)}{2R}=\frac{N!}{2R(N-R)!}\)   (when \(R\leq N\))
    OR
    Total Orientation Independent Circular Permutations Without Repeatition \(=\frac{N!}{2N(N-N)!}=\frac{(N-1)!}{2}\)   (when \(R=N\))
Related Calculators
Linear/Circular Permutations Without Repeatition Calculator
Related Topics
Linear Permutations Without Repeatition,    Fundamental Principle of Counting, Concept of Factorial, Permutation and Combination,    Introduction to Combinatorics
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